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  1. Dynamic subtraction game with function - Mathematics Stack Exchange

    Apr 6, 2020 · The first player to move may remove as many chips as desired, at least one chip but not the whole pile. Thereafter, the players alternate moving, each player not being allowed to …

  2. In terms of the original game, this means that an optimal strategy is for the Bomber is to put weight 1=4 for each mid-edge move and for the Submarine to put weight 1=8 on each of 1 2, 1 …

  3. patient players in subtraction games. In addition to removing s chips from the pile where s is in the subtraction set, S, we allow th whole pile to be taken at all times. Let g(x) represent the …

  4. Subtraction game - Wikipedia

    Nim has a well-known optimal strategy in which the goal at each move is to reach a set of piles whose nim-sum is zero, and this strategy is central to the Sprague–Grundy theorem of optimal …

  5. (Impatient Subtraction) Suppose in a subtraction game with set S, we also let the player remove the whole pile on any move. Prove that the function for this game, g+(x) = g(x 1) + 1 where …

  6. Consider the subtraction game in which you start with a pile of chips and players alternate taking away any number si from the set S = {1, 3, 4} of chips from the heap. The player to take the …

  7. For example, starting with an 8 by 3 board, suppose the first player chomps at (6, 2) gobbling 6 pieces, and then second player chomps at (2, 3) gobbling 4pieces, leaving the following board, …

  8. Dynamic subtraction game - Computer Science Stack Exchange

    Nov 8, 2013 · What is an optimal move for the first player if n = 44? For what values of n does the second player have a win? Now, I know how to solve basic subtraction games, i.e., when …

  9. 1. A subtraction game. Starting with a pile of n chips (here n is a positive integer), two players alternate taking one to four chips. The player who removes the last chip wins. Play this game …

  10. Problem - 1537D - 1537D - Codeforces

    In the first test case, the game ends immediately because Alice cannot make a move. In the second test case, Alice can subtract 2 2 making n = 2 n = 2, then Bob cannot make a move so …